Huawei HCIA-Datacom V2.0 H12-811_V2.0 Exam Dumps: Updated Questions & Answers (October 2026)

An Ethernet switch learns MAC address entries dynamically by examining the source MAC address of incoming frames. When SW1 first receives frames from PC1 on GE1/0/1, it creates a MAC address table entry mapping PC1’s MAC address to that port. If PC1 later sends frames that arrive on GE1/0/2, SW1 updates the learned entry to reflect the new incoming interface. Therefore, option B is correct: SW1 saves the mapping between PC1’s MAC address and GE1/0/2 and removes or overwrites the old mapping associated with GE1/0/1.

Option A is incorrect because a single dynamic MAC address is not normally maintained on two different ports within the same VLAN at the same time; that would cause forwarding ambiguity. Option C is incorrect because a normal move of one MAC address does not require clearing the entire MAC table. Option D is also incorrect because switches update MAC learning dynamically upon receiving new source traffic and do not have to wait for the previous entry to age out. HCIA-Datacom uses this principle to explain MAC address learning, migration, and troubleshooting of loops or host movement in switched Ethernet networks.

To check OSPF-learned routes in the global IP routing table , the correct command is display ip routing-table protocol ospf , so option A is correct. This command filters the routing table and shows only the routes whose source protocol is OSPF. It is especially useful when verifying whether OSPF-learned routes have been successfully installed into the forwarding table after neighbor establishment and LSDB calculation.

Option B , display ospf peer, is used to check OSPF neighbor information and adjacency states, not the routing table. Option C , display ospf interface, shows OSPF-related parameters on interfaces such as timers, network type, and cost. Option D , display ospf routing, displays OSPF route information maintained by the OSPF process itself, but the question specifically asks about routes in the global routing table , which is the RIB used for actual forwarding decisions. HCIA-Datacom distinguishes between protocol-specific route information and the final routing table seen by the device. Understanding this distinction helps engineers verify whether a protocol has only learned topology information or has actually produced usable forwarding entries.

A /27 subnet mask is 255.255.255.224, which means each subnet contains 32 IP addresses. The subnet increments in blocks of 32 in the last octet: 0, 32, 64, 96, 128, 160, 192, 224. The address 192.168.1.200/27 belongs to the subnet 192.168.1.192/27.

For this subnet, the network address is 192.168.1.192, the broadcast address is 192.168.1.223, and the valid host range is from 192.168.1.193 to 192.168.1.222. Therefore, 192.168.1.221/27, 192.168.1.193/27, and 192.168.1.222/27 are all valid host addresses in the same subnet and are reachable at Layer 2 without routing. That makes A, C, and D correct.

Option B is not correct because 192.168.1.192/27 is the network address of the subnet and cannot be assigned to a host by default. This question checks IP subnetting and the ability to identify valid hosts within the same broadcast domain.

Option C is false. In this configuration, the NAT address group test contains the public address range 100.1.23.1 to 100.1.23.254 , and the address group works in PAT mode . Port Address Translation allows multiple different intranet users to share the same public IP address while being distinguished by different transport-layer port numbers. Therefore, intranet users with different private IP addresses do not have to use different post-NAT public IP addresses.

Option A is true because 100.1.23.254 is included in the configured public address pool and can be used for source NAT. Option B is also true because NAT is enabled on GE0/0/2 , so if user traffic does not leave through that interface, the NAT policy may not be applied and public access may fail. Option D is true because the configured source address range includes 192.168.1.100, which falls within 192.168.0.0 to 192.168.255.255. HCIA-Datacom teaches that NAT behavior depends on matching traffic, address pools, PAT or no-PAT mode, and the interface where NAT is enabled. This question mainly tests understanding of source NAT and PAT address-sharing behavior.

When a switch receives an untagged frame from a user host on an access interface , it associates that frame with the VLAN configured on the interface. In this scenario, PC1 and PC2 are in VLAN 10, and GE1/0/2 is an access interface in VLAN 10. After SW1 receives the frame from PC1, it internally associates the frame with VLAN 10 , so option A is correct in the practical VLAN-processing sense used in HCIA-Datacom questions.

When the frame is forwarded out an access interface toward PC2, the switch sends it without a VLAN tag , because end hosts normally do not process 802.1Q tags. Therefore, option D is correct. Option B is incorrect because both hosts are in the same VLAN and can communicate normally; SW1 does not discard the return traffic for that reason. Option C is not correct in the standard VLAN switching model used by Huawei training, because the switch performs forwarding based on VLAN membership and internally processes the frame as belonging to VLAN 10. This question mainly checks understanding of access/trunk behavior and tag handling on ingress and egress.

The IPv6 basic header has a fixed length of 40 bytes and contains eight fields: Version, Traffic Class, Flow Label, Payload Length, Next Header, Hop Limit, Source Address, and Destination Address. The Source IPv6 Address is therefore part of the IPv6 header. Hop Limit is also present and serves a function comparable to the IPv4 TTL field by limiting how many Layer 3 forwarding hops a packet can traverse. Next Header identifies the type of extension header or upper-layer protocol that follows the IPv6 basic header. A source MAC address is not part of the IPv6 header. MAC addresses belong to the data-link-layer frame header, such as an Ethernet header, and are relevant only to the current Layer 2 segment. As an IPv6 packet is routed, Ethernet source and destination MAC addresses can change from hop to hop while the IPv6 source and destination addresses normally remain unchanged end to end. Therefore A, B, and C are IPv6 header fields, while D is not. The correct answer is A, B, and C.

In a WAC + Fit AP architecture, the WAC (Wireless Access Controller) centrally manages and controls the Fit APs, so option A is correct. Service configurations such as SSIDs, security policies, radio parameters, and access control are generally delivered from the WAC to the APs. The Fit AP mainly forwards wireless user traffic and executes the configuration issued by the controller.

Option D is also correct because a Fit AP provides 802.11 wireless access for stations (STAs) and serves as a bridge between the wireless side and the wired network. This is one of its basic roles in enterprise WLAN deployment. Option B is incorrect because users or administrators do not normally need to log in to each Fit AP individually to configure wireless services; centralized management by the WAC is the whole advantage of this architecture. Option C is incorrect because CAPWAP communication between the WAC and AP does not require Layer 2 adjacency ; the WAC and AP can communicate over Layer 3 as long as IP connectivity exists. HCIA-Datacom emphasizes centralized configuration, simplified operations, and scalable deployment as key benefits of WAC + Fit AP networking.

This statement is false because the receiver is one of the fundamental elements of communication. In basic communication theory, a complete communication process requires at least four essential elements: the sender , the information or message content , the transmission medium or channel , and the receiver . If the receiver is missing, communication cannot be completed because there is no endpoint to accept, interpret, or respond to the transmitted information.

In datacom networks, this concept maps directly to real networking scenarios. A source host generates data, the data is carried over some medium such as copper, fiber, or wireless, and a destination host receives the data. Network devices such as switches and routers assist the forwarding process, but the fundamental communication model still includes both communicating endpoints. HCIA-Datacom emphasizes the complete sender-to-receiver process when introducing network communication basics, protocol encapsulation, and forwarding. Therefore, excluding the receiver from the communication elements is conceptually incorrect. The correct understanding is that sender, receiver, information content, and channel together form the essential basis of communication.

Huawei network devices use file extensions to distinguish software images, patches, configuration files, and other packages. A patch package uses the .pat extension, so test.pat is the only option that represents a Huawei patch file. A .cc file is normally associated with a VRP system software package rather than a patch. Configuration data is stored in supported configuration formats and is not identified by the .pat extension. An administrator can transfer the patch file to the device by FTP, SFTP, or another supported file-transfer method and then activate or load it according to the platform ' s patch procedure. The purpose of a patch is to correct defects or vulnerabilities without necessarily replacing the complete system software package. Because the question asks specifically for the file that can be uploaded as a patch to remediate a security vulnerability, the filename ending in .pat is the technically correct selection. The source answer B is therefore consistent with Huawei Datacom file-management conventions.

LACP mode and manual load-balancing mode behave differently when an Eth-Trunk contains a link connected to the wrong peer. In LACP mode, member interfaces exchange LACPDUs and the switches determine which physical links can participate in the same aggregation. GE1/0/1 through GE1/0/3 are correctly connected between SW1 and SW2, so they can form an operational LACP Eth-Trunk. GE1/0/4 is connected to SW3 and cannot successfully negotiate as a member of the SW1-SW2 LAG; it is therefore not used for service forwarding to SW3. This makes A and B true. In manual mode, there is no LACP negotiation to validate that every member terminates on the same peer. If GE1/0/4 is manually placed in the trunk, the device may treat it as a forwarding member and hash some traffic onto that link toward SW3. The trunk does not automatically go Down solely because of that incorrect peer connection. Therefore C is false and D is true.